• ±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000
  • ±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000
  • ±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000
  • ±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000
  • ±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000

±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000

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±1A Constant Current Power Supply AC & DC Constant Current Source ELECDEMO KW-BPVCCS1000

Read Before Purchasing:

(1) The interfaces of the module are clear and its performance is stable. Please combine the information provided by us and then perform functional verification corresponding to the experimental conditions.
(2) The basic parameters of this module are mentioned below. Schematic diagram is not provided. If you have operational problems, please consult customer service.
(3) Before using the module, please read the information of this module to understand power supply and usage restrictions so as to avoid damage to the module due to improper operation.
(4) Real module parameters, functions and pictures are provided. All modules have passed inspection before delivery.

Description:
KW-BPVCCS1000 can be powered by ±5V to ±30V (dual supply) and +5V to +30V (single supply). The module has anti-reverse connection protection of power supply and output current display. Its output current can be adjusted with a knob or controlled by an external input voltage. When inputting 1V, the corresponding output current is 0.2A. It can output AC current. It is suitable for laser, LED constant current drive and sensor excitation control, etc.

Module Parameters:

- Module model: KW-BPVCCS1000
- Module Type: Voltage Controlled Constant Current Source
- Supply voltage: ±5V to ±30V (dual power supply); +5V to +30V (single supply)
- Static power consumption: 60mA (typical)
- Module bandwidth: 26KHz at RL=4Ω
- Current response speed: 25uS
- Input Impedance: 500KΩ
- Maximum tube consumption: 55W
- Current control mode: via module knob; via external input voltage (change control modes by switch)
- Input voltage control range: -5V to +5V or 0 to +5V
- Output current: -1A to +1A; 0 to +1A [switchable (can not output negative current when powered by a single power supply)]
- Output power: 25W max. (active heat dissipation device can be added for long-time operation of high power)
- Load range: 45Ω-25Ω at 1A
- Load regulation: 1%
- Display resolution: 1mA (When outputting AC current, the module will display "AC")
- Module protection: anti-reverse connection protection of power supply
- Module features: display output current; be powered by single power supply and dual power supply. Adjustable output current
- Module application: coil drive, laser constant current drive, LED constant current drive, sensor constant current drive, excitation signal supply, etc.
- Module weight: 135g/0.3lb
- Module Dimensions: 56.5 x 96 x 35mm/2.2 x 3.8 x 1.4" (LxWxH)
- Module heating factor: the larger the output, the more heat it dissipates (the voltage difference between the power supply and the output voltage is too large or the module is damaged)

Package Included:
- 1 x Constant Current Source Module


Introduction of Interfaces:
1. Current display (when outputting AC current, the nixie tube will display "AC")
2. Switch to choose control mode of output current (move upwards for knob control; downwards for control via external input voltage)
3. Control voltage interface (input -5V to +5V and output current -1A to +1A; input 0 to +5V and output current 0 to +1A)
4. Load interface (pay attention to tube consumption control)
5. Power supply interface (support single and dual power supply)
6. Output range selection switch (only positive current can be output when powered by a single power supply)
7. Current regulation (only work when it is controlled via knob)


Precautions:
(1) Because the power consumption of the module is large, its power supply needs to have a certain margin. It is recommended to use a power supply with a current driving capacity that is more than 1.5 times the required output current.
(2) In order to avoid unnecessary interference, it is recommended to use a linear power supply. An electrolytic capacitor above 50V/470uF can be connected in parallel at its input end, and the power supply cannot exceed ±30V.
(3) It is recommended to use a good wire for the output signal to observe the effect. Poor contact and poor-quality cables can cause signal attenuation and excessive noise.
(4) It is recommended to use low-resistance wires for power output, otherwise it may cause excessive wire loss and unstable power output.
(5) Due to the large power consumption and heat generation, please pay attention to ventilation and heat dissipation. You can improve active heat dissipation when it works with high power for a long time.
(6) Because it is a constant current source, it is recommended to confirm the output power and amplitude before connecting a load to avoid damage to the module or load.

FAQ:
Q: When powered by a single power supply or dual power supply, how to wire the modules respectively?
A: When powered by a single power supply, V- does not need to be connected, V+ is connected to power supply positive end, and GND to power supply negative end. When powered by dual power supplies, V+, V-, and GND are respectively connected to power supply positive, negative and GND.

Q: What does module tube consumption mean? What is the function?
A: Module tube consumption refers to the value obtained by subtracting the output power from the input power. The tube consumption needs to be controlled within 55W, otherwise the module may be damaged. (Tube consumption = supply voltage x output current - load resistance x output current2 = Vpower x lout - RL x Iout2; the formula can be used to calculate the minimum load.)

Q: What is the minimum load that the module can drive?
A: The minimum load value is related to several factors, which can be calculated by referring to the above formula. For example: when the supply voltage is ±30V and the output current is 1A, (60 x 1- RL x 12 ≤55W), the load needs to be controlled at 5Ω and above.

Q: Can the module directly drive a coil?
A: Yes, it can. But the tube consumption of the module is must be within 55W. If it is over 55W, a power resistor can be connected to the module in series to protect the module.

Q: Can the module input square wave or pulse?
A: Yes. The module can input square wave or pulse, but the frequency must be within the bandwidth of the module, and the module is compatible with DC input.

Q: Why is the output waveform a square wave when a sine wave is input?
A: Maybe the load resistance is too large, or the power supply voltage is not enough. You can reduce the load and increase the supply voltage.

Q: Can the module output AC constant current?
A: When powered by positive and negative dual power supplies, the module can output constant current AC current.

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